2y^2-26y+60=0

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Solution for 2y^2-26y+60=0 equation:



2y^2-26y+60=0
a = 2; b = -26; c = +60;
Δ = b2-4ac
Δ = -262-4·2·60
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*2}=\frac{12}{4} =3 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*2}=\frac{40}{4} =10 $

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